cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 (edited) [quote name='RandomProddy' date='May 25 2004, 09:51 PM'] The logs cancel by putting the whole thing to an exponent of 6. 1 log6(5-3a) = log6(a2-f) 6^(log6(5-3a)) = 6^(log6((a^2)-f) 5-3a = a^2 - f a^2 +3a - (5+f) = 0 [/quote] Thank you!! I'm sorry guys the f should be a 5 duh to myself!! By the way, I have a graphing calculator... Edited May 26, 2004 by cathgirl Link to comment Share on other sites More sharing options...
Thy Geekdom Come Posted May 26, 2004 Share Posted May 26, 2004 Well this is humbling...I can't remember this! I got a 32 on the math section of the ACT...but I can't remember this! ARGH! Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 I worked it out and got a^2+3a-10 I typed it into my quad prgm and got -5 and 2 so (a-5) and (a+2) Did I do that all right? Link to comment Share on other sites More sharing options...
RandomProddy Posted May 26, 2004 Share Posted May 26, 2004 [quote name='cathgirl' date='May 26 2004, 03:53 AM'] Thank you!! I'm sorry guys the f should be a 5 duh!! [/quote] In that case it's explicitly solvable: a^2 +3a - 10 = 0 x^2 + 3x - 10 = 0 a=1, b=3, c=-10 x = (-b [u]+[/u] (b^2 - 4ac)^1/2) / 2a = -3 [u]+[/u] 7 / 2 = -5 and 2 Link to comment Share on other sites More sharing options...
VeraMaria Posted May 26, 2004 Share Posted May 26, 2004 [quote name='cathgirl' date='May 25 2004, 10:38 PM'] Well, ONE (grrr... I have a ton) is 1 log6(5-3a) = log6(a2-5) (the 6's are little and the a is squared..does that make sense, I can't do sub/superscript on posts) do the log6 cancel each other out? [/quote] omg i am doing the EAXACT SAME THING!!!!!!!!!!!!!!! I took the final today :ph34r: :ph34r: :ph34r: Link to comment Share on other sites More sharing options...
RandomProddy Posted May 26, 2004 Share Posted May 26, 2004 (edited) [quote name='cathgirl' date='May 26 2004, 03:57 AM'] Did I do that all right? [/quote] Think so, put it back into the equation to check. log6(5-3a) = log6(a2-5) a=-5: log6(20) = log6(20) yep a=2: log6(-1) = log6(-1) yep first case it's one-to-one, second case it's infinite-to-infinite and periodic so yep That's correct Edited May 26, 2004 by RandomProddy Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 [quote name='RandomProddy' date='May 25 2004, 10:00 PM'] Think so, put it back into the equation to check. [/quote] That would be a smart thing to do!! By the way...thank you so much!! You are smart!!! (same to you Raphael!!!) Link to comment Share on other sites More sharing options...
1337 k4th0l1x0r Posted May 26, 2004 Share Posted May 26, 2004 [url="http://mcraefamily.com/MathHelp/GeometryTriangleAreaDeterminant.htm"]This site[/url] should help on the triangle area with a matrix calculation. Link to comment Share on other sites More sharing options...
crusader1234 Posted May 26, 2004 Share Posted May 26, 2004 AH ITS LEET!!!! AHH Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 #3 (and you thought you were done helping me ) 3+2i / 5-3i (we did this so long ago, and I can't find how to do it in my book or my notes) Do you multiply it by 5+3i or somethin? I have no idea... Link to comment Share on other sites More sharing options...
He carries me Posted May 26, 2004 Share Posted May 26, 2004 do you have this set equal to something? what are the directions? Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 To simplify it (sorry!) Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 bump (please, this my last one and I can't find out how to do it anywhere!! Link to comment Share on other sites More sharing options...
He carries me Posted May 26, 2004 Share Posted May 26, 2004 hmmm i'm thinkin.... i haven't really done that much with complex numbers i could go pull out my big ole calc book and see if it has anything in there...... Link to comment Share on other sites More sharing options...
cathgirl Posted May 26, 2004 Author Share Posted May 26, 2004 Don't go to too much trouble, please, i feel bad if you search a lot for it!!! Link to comment Share on other sites More sharing options...
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