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cathgirl

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Well, ONE (grrr... I have a ton) is

1 log6(5-3a) = log6(a2-5)
(the 6's are little and the a is squared..does that make sense, I can't do sub/superscript on posts)

do the log6 cancel each other out?

Edited by cathgirl
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1 log6(5-3a) = log6(a2-f)


Grrr. I hated those. Well, I can't really remember exactly. I never really understood those. It didn't help that our teacher had a really thick accent.

I think you're right though. They do cancel out. Oh, somebody who's good at math help!

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Thy Geekdom Come

I'm good at math...but it's been a long time...I do believe that they cancel out.

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Problem # 2 (pple still help w/ the first one please!!! :) )

Find the area of a triangle with the vertices (0,9), (4,6), and (-1, 12)
This uses matrices, this is what I have so far

[ 0 4 -1 ]
[9 6 12 ] + ????? =

I don't know how to get the second one, all I know, is that it is all the same number... :ph34r:

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[quote name='Raphael' date='May 25 2004, 09:46 PM'] I'm good at math...but it's been a long time...I do believe that they cancel out. [/quote]
Thanks! You too Colleen!!

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Thy Geekdom Come

Hehe...you don't need to use matrices for this...hehe...

Graphing Calculator to the rescue!

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[quote name='Raphael' date='May 25 2004, 09:48 PM'] Hehe...you don't need to use matrices for this...hehe...

Graphing Calculator to the rescue! [/quote]
That's what the teacher told us to do...it says to use them!!! :(

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ilovechrist

this is why i'm behind in Math. i take my time (something that's hard for me to do), and i work on them for hours.... boo. wish i could help, but i did 3 Geometry exercises today, and i'm wiped.

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Thy Geekdom Come

Okay...it's been over a year...I don't remember how to do triangle matrices and am trying to remember the trig...

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RandomProddy

[quote name='cathgirl' date='May 26 2004, 03:38 AM'] Well, ONE (grrr... I have a ton) is

1 log6(5-3a) = log6(a2-f)
(the 6's are little and the a is squared..does that make sense, I can't do sub/superscript on posts)

do the log6 cancel each other out? [/quote]
The logs cancel by putting the whole thing to an exponent of 6.

1 log6(5-3a) = log6(a2-f)


6^(log6(5-3a)) = 6^(log6((a^2)-f)

5-3a = a^2 - f

a^2 +3a - (5+f) = 0

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Thy Geekdom Come

[quote] That's what the teacher told us to do...it says to use them!!![/quote]

Then it's time to download a vector calculation program!

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